(1)x0=49/65, x1=f(x2)=11/19 x2=f(x3)=1/5 x3=f(x4)=-1(2)将x1=(4x0-2)/(x0+1)代入x1=x0得 (x0)²备册-3(x0)+2=0 所有悔塌x0=1或x0=2(3)将x(n+1)=(4xn-2)/(xn+1)代入x(n+1)>xn得 1 因为x1=4-6/(xn+1),易得2<6/(xn+1)<3 从而1 所以x0取值范围为(1,2)时仿前宏,满足条件
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(1)易得答案49/65,11/19,1/5,-1(2) 令x=f(x)得到x=1或2(3)x