由二力平衡
F浮=G-F拉=1.96N-0.98N=0.98N
由阿基米德定律,物体所受的浮力等于衫碧排开液体的重力慧辩
∵F浮=ρgV
∴V=F浮/ρg=0.98N÷(1.0×10³kg/m³×9.8N/kg)=0.0001m³
G水=ρgV=1.0×10³kg/m³x×9.8N/kg×0.0001m³=0.98N
所以F浮=G-F=1.96-0.98=0.98N
V排=200ml-100ml=100ml
G排=F浮=0.98N
实验得出或碧举结论即阿基米德定律
F浮=G-F=1.96-0.98=0.98N V排=200ml-100ml=100ml
G排=F浮=0.98N
F浮=G-Fn=1.96N-0.98N=0.98N
∵橘消碧F浮=ρgV
∴V=F浮/ρg=0.98N÷(1.0×10³kg/圆举m³×9.8N/kg)=0.0001m³
G水桥枝=ρgV=1.0×10³kg/m³x×9.8N/kg×0.0001m³=0.98N