n√n/(n²-1)=√n³/(n²-1)==√(n³-n+n)/御瞎(n²-1)=√(n²-1)*n/(n²-1)+n/(n²-1)=√n+n/(n²-1)(n为自然坦念数,且n>镇信空=2))
n根号[n/(n^2-1)]=根号郑前[n^2*n/(n^2-1)]=根喊携清号『[n*(n^2-1)+n]/(n^2-1)』隐旦=根号[n+n/(n^2-1)]